Ladder if or else if statement ~ C Programming

The marks obtained by a student in 5 different subjects are input through the keyboard. The student gets a division as per the following rules:

=> Percentage above or equal to 60 - First Division
=> Percentage between 50 and 59 - Second Division
=> Percentage between 40 and 49 - Third Division
=> Percentage less than 40 - Fail

Method: 1

/*Write a program to calculate the division obtained by the student. There are two ways in which we can write a program for this example. These methods are given below: */

//Method-1
#include< stdio.h >
#include< conio.h >
void main()
{
  int eng,math,com,sci,ss,total;
  float per;
  clrscr();
  printf("Enter Five Subjects Marks\n");
  scanf("%d%d%d%d%d",&eng,&math,&com,&sci,&ss);

  total = eng + math + com + sci + ss ;
  printf("Toal Marks : %d",total);
  per = total * 100.00 / 500;
  printf("\n Percentage : %f", per);

  if(per >= 60)
  {
    printf("\n 1st Division");
  }
  else if(per >= 50)
  {
    printf("\n 2nd Division");
  }
  else if(per >= 40)
  {
    printf("\n 3rd Division");
  }
  else
  {
    printf("\n Sorry Fail");
  }
  getch();
}

Method: 2

//Method-2
#include< stdio.h >
#include< conio.h >
void main()
{
  int eng,math,com,sci,ss,total;
  float per;
  clrscr();
  printf("Enter Five Subjects Marks\n");
  scanf("%d%d%d%d%d",&eng,&math,&com,&sci,&ss);

  total = eng + math + com + sci + ss ;
  printf("Toal Marks : %d",total);
  per = total * 100.00 / 500;
  printf("\n Percentage : %f", per);

  if(per >= 60)
  {
    printf("\n 1st Division");
  }
  if(per >= 50 && per < 60)
  {
    printf("\n 2nd Division");
  }
  if(per >= 40 && per < 50)
  {
    printf("\n 3rd Division");
  }
  if(per < 40)
  {
    printf("\n Sorry Fail");
  }
  getch();
}

C Programming

Ladder if or else if statement

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