Ladder if or else if statement

The marks obtained by a student in 5 different subjects are input through the keyboard. The student gets a division as per the following rules:

=> Percentage above or equal to 60 - First Division
=> Percentage between 50 and 59 - Second Division
=> Percentage between 40 and 49 - Third Division
=> Percentage less than 40 - Fail

Method: 1

/*Write a program to calculate the division obtained by the student. There are two ways in which we can write a program for this example. These methods are given below: */ //Method-1 #include< stdio.h > #include< conio.h > void main() { int eng,math,com,sci,ss,total; float per; clrscr(); printf("Enter Five Subjects Marks\n"); scanf("%d%d%d%d%d",&eng,&math,&com,&sci,&ss); total = eng + math + com + sci + ss ; printf("Toal Marks : %d",total); per = total * 100.00 / 500; printf("\n Percentage : %f", per); if(per >= 60) { printf("\n 1st Division"); } else if(per >= 50) { printf("\n 2nd Division"); } else if(per >= 40) { printf("\n 3rd Division"); } else { printf("\n Sorry Fail"); } getch(); }


Method: 2

//Method-2 #include< stdio.h > #include< conio.h > void main() { int eng,math,com,sci,ss,total; float per; clrscr(); printf("Enter Five Subjects Marks\n"); scanf("%d%d%d%d%d",&eng,&math,&com,&sci,&ss); total = eng + math + com + sci + ss ; printf("Toal Marks : %d",total); per = total * 100.00 / 500; printf("\n Percentage : %f", per); if(per >= 60) { printf("\n 1st Division"); } if(per >= 50 && per < 60) { printf("\n 2nd Division"); } if(per >= 40 && per < 50) { printf("\n 3rd Division"); } if(per < 40) { printf("\n Sorry Fail"); } getch(); }

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